Base | Representation |
---|---|
bin | 110100010011001010… |
… | …1000011000001010100 |
3 | 101201220020012222021021 |
4 | 1220212111003001110 |
5 | 3320003410420200 |
6 | 123332344130524 |
7 | 11054125650055 |
oct | 1504625030124 |
9 | 351806188237 |
10 | 112312201300 |
11 | 436a4345182 |
12 | 19925166a44 |
13 | a78b554860 |
14 | 561630a72c |
15 | 2dc50c941a |
hex | 1a26543054 |
112312201300 has 144 divisors (see below), whose sum is σ = 270035060400. Its totient is φ = 40277053440.
The previous prime is 112312201277. The next prime is 112312201307. The reversal of 112312201300 is 3102213211.
It can be written as a sum of positive squares in 24 ways, for example, as 68626185156 + 43686016144 = 261966^2 + 209012^2 .
It is a super-2 number, since 2×1123122013002 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (112312201307) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 32561976 + ... + 32565424.
It is an arithmetic number, because the mean of its divisors is an integer number (1875243475).
Almost surely, 2112312201300 is an apocalyptic number.
112312201300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 112312201300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (135017530200).
112312201300 is an abundant number, since it is smaller than the sum of its proper divisors (157722859100).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
112312201300 is a wasteful number, since it uses less digits than its factorization.
112312201300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4190 (or 4183 counting only the distinct ones).
The product of its (nonzero) digits is 72, while the sum is 16.
Adding to 112312201300 its reverse (3102213211), we get a palindrome (115414414511).
The spelling of 112312201300 in words is "one hundred twelve billion, three hundred twelve million, two hundred one thousand, three hundred".
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