Base | Representation |
---|---|
bin | 11001101110000000110010… |
… | …111010111100011001100000 |
3 | 112211111111201022220211120022 |
4 | 121232000302322330121200 |
5 | 104311221123413120000 |
6 | 1040323240255533012 |
7 | 32553103246550312 |
oct | 3156006272743140 |
9 | 484444638824508 |
10 | 113113113020000 |
11 | 330500024a0a85 |
12 | 1082a0b482a168 |
13 | 4b166a0234612 |
14 | 1dd09bd6437b2 |
15 | d124e94ba585 |
hex | 66e032ebc660 |
113113113020000 has 60 divisors (see below), whose sum is σ = 278275225045356. Its totient is φ = 45245245200000.
The previous prime is 113113113019943. The next prime is 113113113020027. The reversal of 113113113020000 is 20311311311.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 9 ways as a sum of consecutive naturals, for example, 2827807826 + ... + 2827847825.
Almost surely, 2113113113020000 is an apocalyptic number.
113113113020000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
113113113020000 is an abundant number, since it is smaller than the sum of its proper divisors (165162112025356).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
113113113020000 is an frugal number, since it uses more digits than its factorization.
113113113020000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5655655681 (or 5655655658 counting only the distinct ones).
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 113113113020000 its reverse (20311311311), we get a palindrome (113133424331311).
The spelling of 113113113020000 in words is "one hundred thirteen trillion, one hundred thirteen billion, one hundred thirteen million, twenty thousand".
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