Base | Representation |
---|---|
bin | 1010010010101000111110… |
… | …1011000111111000000000 |
3 | 1111001201220111102011110110 |
4 | 2210222033223013320000 |
5 | 2440342321200212000 |
6 | 40022111344431320 |
7 | 2245336012426455 |
oct | 244521753077000 |
9 | 44051814364413 |
10 | 11315354304000 |
11 | 36728a657204a |
12 | 1328ba9318540 |
13 | 641058300c36 |
14 | 2b19479a982c |
15 | 149511d16850 |
hex | a4a8fac7e00 |
11315354304000 has 160 divisors (see below), whose sum is σ = 37620724860576. Its totient is φ = 3017427763200.
The previous prime is 11315354303987. The next prime is 11315354304073. The reversal of 11315354304000 is 40345351311.
It is a tau number, because it is divible by the number of its divisors (160).
It is a Harshad number since it is a multiple of its sum of digits (30).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 29275069 + ... + 29659068.
Almost surely, 211315354304000 is an apocalyptic number.
11315354304000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
11315354304000 is an abundant number, since it is smaller than the sum of its proper divisors (26305370556576).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11315354304000 is an frugal number, since it uses more digits than its factorization.
11315354304000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 58934173 (or 58934147 counting only the distinct ones).
The product of its (nonzero) digits is 10800, while the sum is 30.
Adding to 11315354304000 its reverse (40345351311), we get a palindrome (11355699655311).
The spelling of 11315354304000 in words is "eleven trillion, three hundred fifteen billion, three hundred fifty-four million, three hundred four thousand".
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