Base | Representation |
---|---|
bin | 10101010001111000… |
… | …00001011010110111 |
3 | 1002111011201120221110 |
4 | 22220330001122313 |
5 | 141344101210320 |
6 | 5125341050103 |
7 | 553050310023 |
oct | 125074013267 |
9 | 32434646843 |
10 | 11424241335 |
11 | 4932760671 |
12 | 2269b56933 |
13 | 1100aa5a20 |
14 | 7a5385383 |
15 | 46ce405e0 |
hex | 2a8f016b7 |
11424241335 has 32 divisors (see below), whose sum is σ = 20540717568. Its totient is φ = 5379707520.
The previous prime is 11424241327. The next prime is 11424241337. The reversal of 11424241335 is 53314242411.
11424241335 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 11424241335 - 23 = 11424241327 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11424241337) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1269121 + ... + 1278090.
It is an arithmetic number, because the mean of its divisors is an integer number (641897424).
Almost surely, 211424241335 is an apocalyptic number.
11424241335 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
11424241335 is a deficient number, since it is larger than the sum of its proper divisors (9116476233).
11424241335 is a wasteful number, since it uses less digits than its factorization.
11424241335 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2547255.
The product of its digits is 11520, while the sum is 30.
Adding to 11424241335 its reverse (53314242411), we get a palindrome (64738483746).
The spelling of 11424241335 in words is "eleven billion, four hundred twenty-four million, two hundred forty-one thousand, three hundred thirty-five".
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