Base | Representation |
---|---|
bin | 1110010100101… |
… | …00010010001000 |
3 | 22101002000000000 |
4 | 13022110102020 |
5 | 221224120112 |
6 | 15531043000 |
7 | 2656134030 |
oct | 712242210 |
9 | 271060000 |
10 | 120145032 |
11 | 61900817 |
12 | 342a0460 |
13 | 1bb77c47 |
14 | 11d568c0 |
15 | a8337dc |
hex | 7294488 |
120145032 has 160 divisors (see below), whose sum is σ = 389716800. Its totient is φ = 34012224.
The previous prime is 120145021. The next prime is 120145033. The reversal of 120145032 is 230541021.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is a junction number, because it is equal to n+sod(n) for n = 120144996 and 120145014.
It is not an unprimeable number, because it can be changed into a prime (120145033) by changing a digit.
It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 1102194 + ... + 1102302.
It is an arithmetic number, because the mean of its divisors is an integer number (2435730).
Almost surely, 2120145032 is an apocalyptic number.
120145032 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 120145032, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (194858400).
120145032 is an abundant number, since it is smaller than the sum of its proper divisors (269571768).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
120145032 is an frugal number, since it uses more digits than its factorization.
120145032 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 149 (or 121 counting only the distinct ones).
The product of its (nonzero) digits is 240, while the sum is 18.
The square root of 120145032 is about 10961.0689259762. The cubic root of 120145032 is about 493.4410457933.
Adding to 120145032 its reverse (230541021), we get a palindrome (350686053).
The spelling of 120145032 in words is "one hundred twenty million, one hundred forty-five thousand, thirty-two".
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