Base | Representation |
---|---|
bin | 10110100110001001… |
… | …00001010001010100 |
3 | 1011022102211100020012 |
4 | 23103010201101110 |
5 | 144321031041040 |
6 | 5323431455352 |
7 | 606422515346 |
oct | 132304412124 |
9 | 34272740205 |
10 | 12131112020 |
11 | 5165773015 |
12 | 2426827558 |
13 | 11b437c4c1 |
14 | 8311cb296 |
15 | 4b001d865 |
hex | 2d3121454 |
12131112020 has 96 divisors (see below), whose sum is σ = 27431308800. Its totient is φ = 4492800000.
The previous prime is 12131111999. The next prime is 12131112101. The reversal of 12131112020 is 2021113121.
It is a junction number, because it is equal to n+sod(n) for n = 12131111986 and 12131112004.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 3030020 + ... + 3034020.
It is an arithmetic number, because the mean of its divisors is an integer number (285742800).
Almost surely, 212131112020 is an apocalyptic number.
12131112020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 12131112020, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (13715654400).
12131112020 is an abundant number, since it is smaller than the sum of its proper divisors (15300196780).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12131112020 is a wasteful number, since it uses less digits than its factorization.
12131112020 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4209 (or 4207 counting only the distinct ones).
The product of its (nonzero) digits is 24, while the sum is 14.
Adding to 12131112020 its reverse (2021113121), we get a palindrome (14152225141).
It can be divided in two parts, 121311 and 12020, that added together give a palindrome (133331).
The spelling of 12131112020 in words is "twelve billion, one hundred thirty-one million, one hundred twelve thousand, twenty".
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