Base | Representation |
---|---|
bin | 10001101001110011000… |
… | …100010111101110111100 |
3 | 11021222020210221022120222 |
4 | 101221303010113232330 |
5 | 124333422443144400 |
6 | 2325143505200512 |
7 | 153434012640344 |
oct | 21516304275674 |
9 | 4258223838528 |
10 | 1213111303100 |
11 | 428528783184 |
12 | 177138630138 |
13 | 8a51ba59c18 |
14 | 42a01987d24 |
15 | 21850cc6185 |
hex | 11a73117bbc |
1213111303100 has 36 divisors (see below), whose sum is σ = 2746905947184. Its totient is φ = 464146932480.
The previous prime is 1213111303073. The next prime is 1213111303109. The reversal of 1213111303100 is 13031113121.
It is a super-2 number, since 2×12131113031002 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1213111303109) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 263717549 + ... + 263722148.
Almost surely, 21213111303100 is an apocalyptic number.
1213111303100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1213111303100 is an abundant number, since it is smaller than the sum of its proper divisors (1533794644084).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1213111303100 is a wasteful number, since it uses less digits than its factorization.
1213111303100 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 527439734 (or 527439727 counting only the distinct ones).
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 1213111303100 its reverse (13031113121), we get a palindrome (1226142416221).
The spelling of 1213111303100 in words is "one trillion, two hundred thirteen billion, one hundred eleven million, three hundred three thousand, one hundred".
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