1300133120 has 144 divisors (see below), whose sum is σ = 3659185152. Its totient is φ = 436346880.

The previous prime is 1300133119. The next prime is 1300133179. The reversal of 1300133120 is 213310031.

It is a super-2 number, since 2×1300133120² = 3380692259441868800, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1300133095 and 1300133104.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 179489 + ... + 186591.

It is an arithmetic number, because the mean of its divisors is an integer number (25411008).

Almost surely, 2^1300133120 is an apocalyptic number.

1300133120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1300133120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1829592576).

1300133120 is an abundant number, since it is smaller than the sum of its proper divisors (2359052032).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1300133120 is a wasteful number, since it uses less digits than its factorization.

1300133120 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7148 (or 7134 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 14.

The square root of 1300133120 is about 36057.3587496367. The cubic root of 1300133120 is about 1091.4301346667.

Adding to 1300133120 its reverse (213310031), we get a palindrome (1513443151).

Subtracting from 1300133120 its reverse (213310031), we obtain a square (1086823089 = 32967²).

The spelling of 1300133120 in words is "one billion, three hundred million, one hundred thirty-three thousand, one hundred twenty".