Base | Representation |
---|---|
bin | 11101100100000010101011… |
… | …101011001100010010111100 |
3 | 122001100210200102112221221100 |
4 | 131210002223223030102330 |
5 | 114020222211313223004 |
6 | 1140310231230133100 |
7 | 36246434014525335 |
oct | 3544025353142274 |
9 | 561323612487840 |
10 | 130020130211004 |
11 | 38479255982750 |
12 | 126ba932651190 |
13 | 5771acbc20647 |
14 | 241701789b28c |
15 | 10071c6985739 |
hex | 7640abacc4bc |
130020130211004 has 36 divisors (see below), whose sum is σ = 358540359067800. Its totient is φ = 39400039457760.
The previous prime is 130020130210973. The next prime is 130020130211077. The reversal of 130020130211004 is 400112031020031.
130020130211004 is a `hidden beast` number, since 1 + 300 + 20 + 130 + 211 + 0 + 0 + 4 = 666.
130020130211004 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a tau number, because it is divible by the number of its divisors (36).
It is a Harshad number since it is a multiple of its sum of digits (18).
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 164166830679 + ... + 164166831470.
It is an arithmetic number, because the mean of its divisors is an integer number (9959454418550).
Almost surely, 2130020130211004 is an apocalyptic number.
It is an amenable number.
130020130211004 is an abundant number, since it is smaller than the sum of its proper divisors (228520228856796).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
130020130211004 is a wasteful number, since it uses less digits than its factorization.
130020130211004 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 328333662170 (or 328333662165 counting only the distinct ones).
The product of its (nonzero) digits is 144, while the sum is 18.
Adding to 130020130211004 its reverse (400112031020031), we get a palindrome (530132161231035).
The spelling of 130020130211004 in words is "one hundred thirty trillion, twenty billion, one hundred thirty million, two hundred eleven thousand, four".
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