130033000100 has 72 divisors (see below), whose sum is σ = 294894250560. Its totient is φ = 49674993280.

The previous prime is 130033000099. The next prime is 130033000103. The reversal of 130033000100 is 1000330031.

It is a super-2 number, since 2×130033000100² (a number of 23 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (130033000103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 1458611 + ... + 1545189.

It is an arithmetic number, because the mean of its divisors is an integer number (4095753480).

Almost surely, 2^130033000100 is an apocalyptic number.

130033000100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 130033000100, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (147447125280).

130033000100 is an abundant number, since it is smaller than the sum of its proper divisors (164861250460).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

130033000100 is a wasteful number, since it uses less digits than its factorization.

130033000100 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 87269 (or 87262 counting only the distinct ones).

The product of its (nonzero) digits is 27, while the sum is 11.

Adding to 130033000100 its reverse (1000330031), we get a palindrome (131033330131).

It can be divided in two parts, 13003 and 3000100, that added together give a palindrome (3013103).

The spelling of 130033000100 in words is "one hundred thirty billion, thirty-three million, one hundred", and thus it is an aban number.