Base | Representation |
---|---|
bin | 11101100100010000000111… |
… | …001100000000000100011111 |
3 | 122001102011220101202111122000 |
4 | 131210100013030000010133 |
5 | 114020441224403041343 |
6 | 1140321014153453343 |
7 | 36250454244461052 |
oct | 3544200714000437 |
9 | 561364811674560 |
10 | 130034550440223 |
11 | 38484385803360 |
12 | 12701697a11253 |
13 | 5773289604660 |
14 | 24179c4ac2a99 |
15 | 100776c925ed3 |
hex | 76440730011f |
130034550440223 has 64 divisors (see below), whose sum is σ = 230032970280960. Its totient is φ = 71554034275200.
The previous prime is 130034550440183. The next prime is 130034550440257. The reversal of 130034550440223 is 322044055430031.
130034550440223 is a `hidden beast` number, since 1 + 3 + 0 + 0 + 345 + 50 + 4 + 40 + 223 = 666.
It is not a de Polignac number, because 130034550440223 - 26 = 130034550440159 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130034550440293) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 275821711 + ... + 276292752.
It is an arithmetic number, because the mean of its divisors is an integer number (3594265160640).
Almost surely, 2130034550440223 is an apocalyptic number.
130034550440223 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
130034550440223 is a deficient number, since it is larger than the sum of its proper divisors (99998419840737).
130034550440223 is a wasteful number, since it uses less digits than its factorization.
130034550440223 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 552114557 (or 552114551 counting only the distinct ones).
The product of its (nonzero) digits is 172800, while the sum is 36.
The spelling of 130034550440223 in words is "one hundred thirty trillion, thirty-four billion, five hundred fifty million, four hundred forty thousand, two hundred twenty-three".
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