13011310000 has 150 divisors (see below), whose sum is σ = 34115720100. Its totient is φ = 4803552000.

The previous prime is 13011309989. The next prime is 13011310007. The reversal of 13011310000 is 1311031.

It is a super-2 number, since 2×13011310000² (a number of 21 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (10).

It is not an unprimeable number, because it can be changed into a prime (13011310007) by changing a digit.

It is a polite number, since it can be written in 29 ways as a sum of consecutive naturals, for example, 1686151 + ... + 1693849.

It is an arithmetic number, because the mean of its divisors is an integer number (227438134).

Almost surely, 2^13011310000 is an apocalyptic number.

13011310000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13011310000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (17057860050).

13011310000 is an abundant number, since it is smaller than the sum of its proper divisors (21104410100).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13011310000 is an equidigital number, since it uses as much as digits as its factorization.

13011310000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7753 (or 7719 counting only the distinct ones).

The product of its (nonzero) digits is 9, while the sum is 10.

Adding to 13011310000 its reverse (1311031), we get a palindrome (13012621031).

The spelling of 13011310000 in words is "thirteen billion, eleven million, three hundred ten thousand".