131000204031110 has 16 divisors (see below), whose sum is σ = 235800788494032. Its totient is φ = 52399988004000.

The previous prime is 131000204030953. The next prime is 131000204031133. The reversal of 131000204031110 is 11130402000131.

It is a super-2 number, since 2×131000204031110² (a number of 29 digits) contains 22 as substring.

It is a Curzon number.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5675621 + ... + 17152640.

It is an arithmetic number, because the mean of its divisors is an integer number (14737549280877).

Almost surely, 2^{131000204031110} is an apocalyptic number.

131000204031110 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

131000204031110 is a deficient number, since it is larger than the sum of its proper divisors (104800584462922).

131000204031110 is a wasteful number, since it uses less digits than its factorization.

131000204031110 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 23402119.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 131000204031110 its reverse (11130402000131), we get a palindrome (142130606031241).

The spelling of 131000204031110 in words is "one hundred thirty-one trillion, two hundred four million, thirty-one thousand, one hundred ten".