Base | Representation |
---|---|
bin | 1011111010100001011011… |
… | …0000101000111110011100 |
3 | 1201101100110202112211121021 |
4 | 2332220112300220332130 |
5 | 3204112331204233200 |
6 | 43510023251413524 |
7 | 2521306002422533 |
oct | 276502660507634 |
9 | 51340422484537 |
10 | 13100032102300 |
11 | 41a0768671820 |
12 | 1576a5a2b42a4 |
13 | 7404350279b0 |
14 | 33408b44131a |
15 | 17ab6661341a |
hex | bea16c28f9c |
13100032102300 has 144 divisors (see below), whose sum is σ = 33400091257344. Its totient is φ = 4396785120000.
The previous prime is 13100032102279. The next prime is 13100032102307. The reversal of 13100032102300 is 320123000131.
It is a super-2 number, since 2×131000321023002 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13100032102307) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 169144585 + ... + 169222015.
It is an arithmetic number, because the mean of its divisors is an integer number (231945078176).
Almost surely, 213100032102300 is an apocalyptic number.
13100032102300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 13100032102300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (16700045628672).
13100032102300 is an abundant number, since it is smaller than the sum of its proper divisors (20300059155044).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13100032102300 is a wasteful number, since it uses less digits than its factorization.
13100032102300 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 89300 (or 89293 counting only the distinct ones).
The product of its (nonzero) digits is 108, while the sum is 16.
Adding to 13100032102300 its reverse (320123000131), we get a palindrome (13420155102431).
The spelling of 13100032102300 in words is "thirteen trillion, one hundred billion, thirty-two million, one hundred two thousand, three hundred".
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