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1310011132020 = 2235234003237143
BaseRepresentation
bin10011000100000010101…
…111111000100001110100
311122020100221001122121120
4103010002233320201310
5132430400322211040
62441451044543540
7163434203616243
oct23040257704164
94566327048546
101310011132020
1146563314a918
12191a800b1bb0
13966c21b17b6
1447594da895a
1524122c817d0
hex13102bf8874

1310011132020 has 96 divisors (see below), whose sum is σ = 3828483090432. Its totient is φ = 334062883968.

The previous prime is 1310011132013. The next prime is 1310011132021. The reversal of 1310011132020 is 202311100131.

It is a happy number.

It is a super-2 number, since 2×13100111320202 (a number of 25 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1310011132021) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 5405569 + ... + 5642711.

It is an arithmetic number, because the mean of its divisors is an integer number (39880032192).

Almost surely, 21310011132020 is an apocalyptic number.

1310011132020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1310011132020, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1914241545216).

1310011132020 is an abundant number, since it is smaller than the sum of its proper divisors (2518471958412).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1310011132020 is a wasteful number, since it uses less digits than its factorization.

1310011132020 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 241181 (or 241179 counting only the distinct ones).

The product of its (nonzero) digits is 36, while the sum is 15.

Adding to 1310011132020 its reverse (202311100131), we get a palindrome (1512322232151).

The spelling of 1310011132020 in words is "one trillion, three hundred ten billion, eleven million, one hundred thirty-two thousand, twenty".

Divisors: 1 2 3 4 5 6 10 12 15 20 23 30 46 60 69 92 115 138 230 276 345 460 690 1380 4003 8006 12009 16012 20015 24018 40030 48036 60045 80060 92069 120090 184138 237143 240180 276207 368276 460345 474286 552414 711429 920690 948572 1104828 1185715 1381035 1422858 1841380 2371430 2762070 2845716 3557145 4742860 5454289 5524140 7114290 10908578 14228580 16362867 21817156 27271445 32725734 54542890 65451468 81814335 109085780 163628670 327257340 949283429 1898566858 2847850287 3797133716 4746417145 5695700574 9492834290 11391401148 14239251435 18985668580 21833518867 28478502870 43667037734 56957005740 65500556601 87334075468 109167594335 131001113202 218335188670 262002226404 327502783005 436670377340 655005566010 1310011132020