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13103301011220 = 2233573466481749
BaseRepresentation
bin1011111010101101100110…
…0110100010011100010100
31201101122220120120121122000
42332223121212202130110
53204141030024324340
643511323503435300
72521453004613330
oct276533146423424
951348816517560
1013103301011220
1141a2095900442
121577610bb5b30
13740836342524
143342bb6467c0
1517aca85c3d30
hexbead99a2714

13103301011220 has 96 divisors (see below), whose sum is σ = 46589514720000. Its totient is φ = 2995040230272.

The previous prime is 13103301011147. The next prime is 13103301011221. The reversal of 13103301011220 is 2211010330131.

13103301011220 is a `hidden beast` number, since 1 + 3 + 10 + 330 + 101 + 1 + 220 = 666.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a junction number, because it is equal to n+sod(n) for n = 13103301011193 and 13103301011202.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13103301011221) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1733237095 + ... + 1733244654.

It is an arithmetic number, because the mean of its divisors is an integer number (485307445000).

Almost surely, 213103301011220 is an apocalyptic number.

13103301011220 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13103301011220 is an abundant number, since it is smaller than the sum of its proper divisors (33486213708780).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13103301011220 is a wasteful number, since it uses less digits than its factorization.

13103301011220 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3466481774 (or 3466481766 counting only the distinct ones).

The product of its (nonzero) digits is 108, while the sum is 18.

Adding to 13103301011220 its reverse (2211010330131), we get a palindrome (15314311341351).

The spelling of 13103301011220 in words is "thirteen trillion, one hundred three billion, three hundred one million, eleven thousand, two hundred twenty".

Divisors: 1 2 3 4 5 6 7 9 10 12 14 15 18 20 21 27 28 30 35 36 42 45 54 60 63 70 84 90 105 108 126 135 140 180 189 210 252 270 315 378 420 540 630 756 945 1260 1890 3780 3466481749 6932963498 10399445247 13865926996 17332408745 20798890494 24265372243 31198335741 34664817490 41597780988 48530744486 51997226235 62396671482 69329634980 72796116729 93595007223 97061488972 103994452470 121326861215 124793342964 145592233458 155991678705 187190014446 207988904940 218388350187 242653722430 291184466916 311983357410 363980583645 374380028892 436776700374 467975036115 485307444860 623966714820 655165050561 727961167290 873553400748 935950072230 1091941750935 1310330101122 1455922334580 1871900144460 2183883501870 2620660202244 3275825252805 4367767003740 6551650505610 13103301011220