1311132020 has 96 divisors (see below), whose sum is σ = 3194069760. Its totient is φ = 447349760.

The previous prime is 1311132019. The next prime is 1311132029. The reversal of 1311132020 is 202311131.

It is a junction number, because it is equal to n+sod(n) for n = 1311131986 and 1311132004.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1311132029) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 265736 + ... + 270624.

It is an arithmetic number, because the mean of its divisors is an integer number (33271560).

Almost surely, 2^1311132020 is an apocalyptic number.

1311132020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1311132020, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1597034880).

1311132020 is an abundant number, since it is smaller than the sum of its proper divisors (1882937740).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1311132020 is a wasteful number, since it uses less digits than its factorization.

1311132020 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4985 (or 4983 counting only the distinct ones).

The product of its (nonzero) digits is 36, while the sum is 14.

The square root of 1311132020 is about 36209.5570257356. The cubic root of 1311132020 is about 1094.4992657817.

Adding to 1311132020 its reverse (202311131), we get a palindrome (1513443151).

It can be divided in two parts, 1311 and 132020, that added together give a palindrome (133331).

The spelling of 1311132020 in words is "one billion, three hundred eleven million, one hundred thirty-two thousand, twenty".