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1311142044400 = 245210138338467
BaseRepresentation
bin10011000101000110001…
…001111110001011110000
311122100021202001221202021
4103011012021332023300
5132440204330410100
62442155204201224
7163504215331006
oct23050611761360
94570252057667
101311142044400
11466063559051
12192136999214
1396842596816
1447661272a76
152418c1c1a1a
hex1314627e2f0

1311142044400 has 120 divisors (see below), whose sum is σ = 3182412834864. Its totient is φ = 519067392000.

The previous prime is 1311142044397. The next prime is 1311142044403. The reversal of 1311142044400 is 44402411131.

It is an interprime number because it is at equal distance from previous prime (1311142044397) and next prime (1311142044403).

It is a Harshad number since it is a multiple of its sum of digits (25).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1311142044403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 154848967 + ... + 154857433.

Almost surely, 21311142044400 is an apocalyptic number.

1311142044400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1311142044400, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1591206417432).

1311142044400 is an abundant number, since it is smaller than the sum of its proper divisors (1871270790464).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1311142044400 is a wasteful number, since it uses less digits than its factorization.

1311142044400 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12419 (or 12408 counting only the distinct ones).

The product of its (nonzero) digits is 1536, while the sum is 25.

Adding to 1311142044400 its reverse (44402411131), we get a palindrome (1355544455531).

The spelling of 1311142044400 in words is "one trillion, three hundred eleven billion, one hundred forty-two million, forty-four thousand, four hundred".

Divisors: 1 2 4 5 8 10 16 20 25 40 50 80 100 101 200 202 400 404 505 808 1010 1616 2020 2525 3833 4040 5050 7666 8080 8467 10100 15332 16934 19165 20200 30664 33868 38330 40400 42335 61328 67736 76660 84670 95825 135472 153320 169340 191650 211675 306640 338680 383300 387133 423350 677360 766600 774266 846700 855167 1533200 1548532 1693400 1710334 1935665 3097064 3386800 3420668 3871330 4275835 6194128 6841336 7742660 8551670 9678325 13682672 15485320 17103340 19356650 21379175 30970640 32454011 34206680 38713300 42758350 64908022 68413360 77426600 85516700 129816044 154853200 162270055 171033400 259632088 324540110 342066800 519264176 649080220 811350275 1298160440 1622700550 2596320880 3245401100 3277855111 6490802200 6555710222 12981604400 13111420444 16389275555 26222840888 32778551110 52445681776 65557102220 81946377775 131114204440 163892755550 262228408880 327785511100 655571022200 1311142044400