1311201602040 has 128 divisors (see below), whose sum is σ = 4291479429120. Its totient is φ = 317846745600.

The previous prime is 1311201602021. The next prime is 1311201602047. The reversal of 1311201602040 is 402061021131.

It is a junction number, because it is equal to n+sod(n) for n = 1311201601998 and 1311201602016.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1311201602047) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 36983202 + ... + 37018638.

It is an arithmetic number, because the mean of its divisors is an integer number (33527183040).

Almost surely, 2^{1311201602040} is an apocalyptic number.

1311201602040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

1311201602040 is an abundant number, since it is smaller than the sum of its proper divisors (2980277827080).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1311201602040 is a wasteful number, since it uses less digits than its factorization.

1311201602040 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 63493 (or 63489 counting only the distinct ones).

The product of its (nonzero) digits is 288, while the sum is 21.

Adding to 1311201602040 its reverse (402061021131), we get a palindrome (1713262623171).

The spelling of 1311201602040 in words is "one trillion, three hundred eleven billion, two hundred one million, six hundred two thousand, forty".