Base | Representation |
---|---|
bin | 1011111011111000000111… |
… | …1100111000011101100010 |
3 | 1201110120112201012021202200 |
4 | 2332332001330320131202 |
5 | 3210003012124410200 |
6 | 43524432505154030 |
7 | 2523061511423265 |
oct | 276760174703542 |
9 | 51416481167680 |
10 | 13123305310050 |
11 | 41aa6207a6211 |
12 | 157b47448b916 |
13 | 7426a3893a40 |
14 | 33525832acdc |
15 | 17b5798dd800 |
hex | bef81f38762 |
13123305310050 has 144 divisors (see below), whose sum is σ = 37981279620648. Its totient is φ = 3229400678400.
The previous prime is 13123305310033. The next prime is 13123305310051. The reversal of 13123305310050 is 5001350332131.
13123305310050 is a `hidden beast` number, since 1 + 3 + 12 + 330 + 5 + 310 + 0 + 5 + 0 = 666.
It can be written as a sum of positive squares in 12 ways, for example, as 477877716369 + 12645427593681 = 691287^2 + 3556041^2 .
It is a super-2 number, since 2×131233053100502 (a number of 27 digits) contains 22 as substring.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 13123305309996 and 13123305310023.
It is not an unprimeable number, because it can be changed into a prime (13123305310051) by changing a digit.
It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 19637410 + ... + 20294690.
Almost surely, 213123305310050 is an apocalyptic number.
13123305310050 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is a practical number, because each smaller number is the sum of distinct divisors of 13123305310050, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (18990639810324).
13123305310050 is an abundant number, since it is smaller than the sum of its proper divisors (24857974310598).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13123305310050 is a wasteful number, since it uses less digits than its factorization.
13123305310050 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 660725 (or 660717 counting only the distinct ones).
The product of its (nonzero) digits is 4050, while the sum is 27.
Adding to 13123305310050 its reverse (5001350332131), we get a palindrome (18124655642181).
The spelling of 13123305310050 in words is "thirteen trillion, one hundred twenty-three billion, three hundred five million, three hundred ten thousand, fifty".
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