Base | Representation |
---|---|
bin | 11101111010001010010010… |
… | …110010100011001111110000 |
3 | 122020202010001220110011211102 |
4 | 131322022102302203033300 |
5 | 114220123142032214100 |
6 | 1143432411345103532 |
7 | 36464314034266154 |
oct | 3572122262431760 |
9 | 566663056404742 |
10 | 131540131132400 |
11 | 38a04946864341 |
12 | 12905437927ba8 |
13 | 5852247c75083 |
14 | 246a80d5ad064 |
15 | 10319d9bcdcd5 |
hex | 77a292ca33f0 |
131540131132400 has 60 divisors (see below), whose sum is σ = 317851900270872. Its totient is φ = 52311913393920.
The previous prime is 131540131132331. The next prime is 131540131132433. The reversal of 131540131132400 is 4231131045131.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 950365274 + ... + 950503673.
Almost surely, 2131540131132400 is an apocalyptic number.
131540131132400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
131540131132400 is an abundant number, since it is smaller than the sum of its proper divisors (186311769138472).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131540131132400 is a wasteful number, since it uses less digits than its factorization.
131540131132400 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1900869138 (or 1900869127 counting only the distinct ones).
The product of its (nonzero) digits is 4320, while the sum is 29.
Adding to 131540131132400 its reverse (4231131045131), we get a palindrome (135771262177531).
The spelling of 131540131132400 in words is "one hundred thirty-one trillion, five hundred forty billion, one hundred thirty-one million, one hundred thirty-two thousand, four hundred".
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