Base | Representation |
---|---|
bin | 100111010101111… |
… | …1100110101010010 |
3 | 10102000002021102000 |
4 | 1032223330311102 |
5 | 10200424103320 |
6 | 334555134430 |
7 | 44500016640 |
oct | 11653746522 |
9 | 3360067360 |
10 | 1320144210 |
11 | 618206980 |
12 | 30a144416 |
13 | 18066bc28 |
14 | c7486190 |
15 | 7ad6dc90 |
hex | 4eafcd52 |
1320144210 has 128 divisors (see below), whose sum is σ = 4389120000. Its totient is φ = 274311360.
The previous prime is 1320144157. The next prime is 1320144211. The reversal of 1320144210 is 124410231.
1320144210 is a `hidden beast` number, since 13 + 201 + 442 + 10 = 666.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is not an unprimeable number, because it can be changed into a prime (1320144211) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 10960 + ... + 52539.
It is an arithmetic number, because the mean of its divisors is an integer number (34290000).
Almost surely, 21320144210 is an apocalyptic number.
1320144210 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is a practical number, because each smaller number is the sum of distinct divisors of 1320144210, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (2194560000).
1320144210 is an abundant number, since it is smaller than the sum of its proper divisors (3068975790).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1320144210 is a wasteful number, since it uses less digits than its factorization.
1320144210 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 63533 (or 63527 counting only the distinct ones).
The product of its (nonzero) digits is 192, while the sum is 18.
The square root of 1320144210 is about 36333.7888197749. The cubic root of 1320144210 is about 1097.0012567062.
Adding to 1320144210 its reverse (124410231), we get a palindrome (1444554441).
It can be divided in two parts, 1320 and 144210, that added together give a triangular number (145530 = T539).
The spelling of 1320144210 in words is "one billion, three hundred twenty million, one hundred forty-four thousand, two hundred ten".
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