Base | Representation |
---|---|
bin | 111101100110111110… |
… | …1000001010101110000 |
3 | 110122111111222001220220 |
4 | 1323031331001111300 |
5 | 4131424403010212 |
6 | 140440233133040 |
7 | 12362424241461 |
oct | 1731575012560 |
9 | 418444861826 |
10 | 132304344432 |
11 | 51123398217 |
12 | 2178455a180 |
13 | c62640b250 |
14 | 6591548d68 |
15 | 36952e238c |
hex | 1ecdf41570 |
132304344432 has 80 divisors (see below), whose sum is σ = 389729118240. Its totient is φ = 38314377216.
The previous prime is 132304344409. The next prime is 132304344433. The reversal of 132304344432 is 234443403231.
It is a happy number.
It is a junction number, because it is equal to n+sod(n) for n = 132304344393 and 132304344402.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (132304344433) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6225457 + ... + 6246672.
It is an arithmetic number, because the mean of its divisors is an integer number (4871613978).
Almost surely, 2132304344432 is an apocalyptic number.
132304344432 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
132304344432 is an abundant number, since it is smaller than the sum of its proper divisors (257424773808).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
132304344432 is a wasteful number, since it uses less digits than its factorization.
132304344432 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12472170 (or 12472164 counting only the distinct ones).
The product of its (nonzero) digits is 82944, while the sum is 33.
Adding to 132304344432 its reverse (234443403231), we get a palindrome (366747747663).
The spelling of 132304344432 in words is "one hundred thirty-two billion, three hundred four million, three hundred forty-four thousand, four hundred thirty-two".
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