Base | Representation |
---|---|
bin | 11110010001000100001011… |
… | …011000110000011111110000 |
3 | 122110022120210100222100202120 |
4 | 132101010023120300133300 |
5 | 114421420200241210100 |
6 | 1151035440135114240 |
7 | 40016114540555043 |
oct | 3621041330603760 |
9 | 573276710870676 |
10 | 133114112444400 |
11 | 3946141821939a |
12 | 12b1a4a6b12980 |
13 | 59377b75b3529 |
14 | 24c2a864dcc5a |
15 | 105c90be6c0a0 |
hex | 79110b6307f0 |
133114112444400 has 60 divisors (see below), whose sum is σ = 426408873534072. Its totient is φ = 35497096651520.
The previous prime is 133114112444363. The next prime is 133114112444447. The reversal of 133114112444400 is 4444211411331.
It is a tau number, because it is divible by the number of its divisors (60).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 55464212319 + ... + 55464214718.
Almost surely, 2133114112444400 is an apocalyptic number.
133114112444400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
133114112444400 is an abundant number, since it is smaller than the sum of its proper divisors (293294761089672).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
133114112444400 is a wasteful number, since it uses less digits than its factorization.
133114112444400 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 110928427058 (or 110928427047 counting only the distinct ones).
The product of its (nonzero) digits is 18432, while the sum is 33.
Adding to 133114112444400 its reverse (4444211411331), we get a palindrome (137558323855731).
The spelling of 133114112444400 in words is "one hundred thirty-three trillion, one hundred fourteen billion, one hundred twelve million, four hundred forty-four thousand, four hundred".
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