Base | Representation |
---|---|
bin | 110011011101… |
… | …100101100100 |
3 | 221101101112100 |
4 | 303131211210 |
5 | 11423144112 |
6 | 1201052100 |
7 | 222444666 |
oct | 63354544 |
9 | 27341470 |
10 | 13490532 |
11 | 7684700 |
12 | 4627030 |
13 | 2a44583 |
14 | 1b12536 |
15 | 12b72dc |
hex | cdd964 |
13490532 has 108 divisors (see below), whose sum is σ = 39697840. Its totient is φ = 3849120.
The previous prime is 13490509. The next prime is 13490573. The reversal of 13490532 is 23509431.
It is a hoax number, since the sum of its digits (27) coincides with the sum of the digits of its distinct prime factors.
It is a plaindrome in base 7.
It is a zygodrome in base 7.
It is a junction number, because it is equal to n+sod(n) for n = 13490496 and 13490505.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 35 ways as a sum of consecutive naturals, for example, 82683 + ... + 82845.
Almost surely, 213490532 is an apocalyptic number.
13490532 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 13490532, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (19848920).
13490532 is an abundant number, since it is smaller than the sum of its proper divisors (26207308).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13490532 is a wasteful number, since it uses less digits than its factorization.
13490532 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 214 (or 198 counting only the distinct ones).
The product of its (nonzero) digits is 3240, while the sum is 27.
The square root of 13490532 is about 3672.9459565858. The cubic root of 13490532 is about 238.0544799134.
Adding to 13490532 its reverse (23509431), we get a palindrome (36999963).
It can be divided in two parts, 13 and 490532, that added together give a triangular number (490545 = T990).
The spelling of 13490532 in words is "thirteen million, four hundred ninety thousand, five hundred thirty-two".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.068 sec. • engine limits •