13540410304000 has 160 divisors (see below), whose sum is σ = 33865917969312. Its totient is φ = 5399792640000.

The previous prime is 13540410303997. The next prime is 13540410304007. The reversal of 13540410304000 is 40301404531.

It is a tau number, because it is divible by the number of its divisors (160).

It is a super-2 number, since 2×13540410304000² (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (25).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13540410304007) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 20864410 + ... + 21503590.

Almost surely, 2^{13540410304000} is an apocalyptic number.

13540410304000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13540410304000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (16932958984656).

13540410304000 is an abundant number, since it is smaller than the sum of its proper divisors (20325507665312).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13540410304000 is an frugal number, since it uses more digits than its factorization.

13540410304000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 639545 (or 639519 counting only the distinct ones).

The product of its (nonzero) digits is 2880, while the sum is 25.

Adding to 13540410304000 its reverse (40301404531), we get a palindrome (13580711708531).

The spelling of 13540410304000 in words is "thirteen trillion, five hundred forty billion, four hundred ten million, three hundred four thousand".