Base | Representation |
---|---|
bin | 10100001001001011000… |
… | …110010010101100000000 |
3 | 11220022222000122212100100 |
4 | 110021023012102230000 |
5 | 140134410242104140 |
6 | 2535524422322400 |
7 | 202002512563563 |
oct | 24111306225400 |
9 | 4808860585310 |
10 | 1384239409920 |
11 | 494064072734 |
12 | 1a4336b89400 |
13 | a06c1626023 |
14 | 4add73984da |
15 | 260196aa530 |
hex | 1424b192b00 |
1384239409920 has 108 divisors (see below), whose sum is σ = 4789324206576. Its totient is φ = 369130506240.
The previous prime is 1384239409901. The next prime is 1384239409939. The reversal of 1384239409920 is 299049324831.
1384239409920 is a `hidden beast` number, since 1 + 384 + 239 + 4 + 0 + 9 + 9 + 20 = 666.
It is an interprime number because it is at equal distance from previous prime (1384239409901) and next prime (1384239409939).
It is a super-2 number, since 2×13842394099202 (a number of 25 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 60068316 + ... + 60091355.
Almost surely, 21384239409920 is an apocalyptic number.
1384239409920 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1384239409920 is an abundant number, since it is smaller than the sum of its proper divisors (3405084796656).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1384239409920 is a wasteful number, since it uses less digits than its factorization.
1384239409920 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 120159698 (or 120159681 counting only the distinct ones).
The product of its (nonzero) digits is 3359232, while the sum is 54.
The spelling of 1384239409920 in words is "one trillion, three hundred eighty-four billion, two hundred thirty-nine million, four hundred nine thousand, nine hundred twenty".
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