139908240 has 120 divisors (see below), whose sum is σ = 480891840. Its totient is φ = 36433152.

The previous prime is 139908233. The next prime is 139908257. The reversal of 139908240 is 42809931.

It is a tau number, because it is divible by the number of its divisors (120).

It is a hoax number, since the sum of its digits (36) coincides with the sum of the digits of its distinct prime factors.

It is a Harshad number since it is a multiple of its sum of digits (36).

It is a junction number, because it is equal to n+sod(n) for n = 139908195 and 139908204.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 28701 + ... + 33219.

It is an arithmetic number, because the mean of its divisors is an integer number (4007432).

Almost surely, 2^139908240 is an apocalyptic number.

139908240 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 139908240, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (240445920).

139908240 is an abundant number, since it is smaller than the sum of its proper divisors (340983600).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

139908240 is a wasteful number, since it uses less digits than its factorization.

139908240 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4581 (or 4572 counting only the distinct ones).

The product of its (nonzero) digits is 15552, while the sum is 36.

The square root of 139908240 is about 11828.2813629031. The cubic root of 139908240 is about 519.1359417583.

The spelling of 139908240 in words is "one hundred thirty-nine million, nine hundred eight thousand, two hundred forty".