1421340034000 has 80 divisors (see below), whose sum is σ = 3480304389120. Its totient is φ = 561339292800.

The previous prime is 1421340033929. The next prime is 1421340034039. The reversal of 1421340034000 is 4300431241.

It is a tau number, because it is divible by the number of its divisors (80).

It is a super-2 number, since 2×1421340034000² (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4339912 + ... + 4655911.

It is an arithmetic number, because the mean of its divisors is an integer number (43503804864).

Almost surely, 2^{1421340034000} is an apocalyptic number.

1421340034000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

1421340034000 is an abundant number, since it is smaller than the sum of its proper divisors (2058964355120).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1421340034000 is an equidigital number, since it uses as much as digits as its factorization.

1421340034000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8995925 (or 8995909 counting only the distinct ones).

The product of its (nonzero) digits is 1152, while the sum is 22.

Adding to 1421340034000 its reverse (4300431241), we get a palindrome (1425640465241).

The spelling of 1421340034000 in words is "one trillion, four hundred twenty-one billion, three hundred forty million, thirty-four thousand".