Base | Representation |
---|---|
bin | 1100111011010101000101… |
… | …1001001101000111101100 |
3 | 1212022210022010220022202112 |
4 | 3032311101121031013230 |
5 | 3330333032030004200 |
6 | 50121315042143152 |
7 | 2664612415346141 |
oct | 316652131150754 |
9 | 55283263808675 |
10 | 14213412344300 |
11 | 458a9687a8654 |
12 | 17167a3051ab8 |
13 | 7c141bbb9010 |
14 | 371d0b9743c8 |
15 | 199acbac5535 |
hex | ced5164d1ec |
14213412344300 has 36 divisors (see below), whose sum is σ = 33215651312256. Its totient is φ = 5248029172800.
The previous prime is 14213412344279. The next prime is 14213412344399. The reversal of 14213412344300 is 344321431241.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 5466695756 + ... + 5466698355.
It is an arithmetic number, because the mean of its divisors is an integer number (922656980896).
Almost surely, 214213412344300 is an apocalyptic number.
14213412344300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
14213412344300 is an abundant number, since it is smaller than the sum of its proper divisors (19002238967956).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
14213412344300 is a wasteful number, since it uses less digits than its factorization.
14213412344300 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10933394138 (or 10933394131 counting only the distinct ones).
The product of its (nonzero) digits is 27648, while the sum is 32.
Adding to 14213412344300 its reverse (344321431241), we get a palindrome (14557733775541).
The spelling of 14213412344300 in words is "fourteen trillion, two hundred thirteen billion, four hundred twelve million, three hundred forty-four thousand, three hundred".
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