1431214443100 has 72 divisors (see below), whose sum is σ = 3354277843728. Its totient is φ = 526925337600.

The previous prime is 1431214443053. The next prime is 1431214443149. The reversal of 1431214443100 is 13444121341.

It is a super-3 number, since 3×1431214443100³ (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 1135261 + ... + 2037460.

It is an arithmetic number, because the mean of its divisors is an integer number (46587192274).

Almost surely, 2^{1431214443100} is an apocalyptic number.

1431214443100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

1431214443100 is an abundant number, since it is smaller than the sum of its proper divisors (1923063400628).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1431214443100 is a wasteful number, since it uses less digits than its factorization.

1431214443100 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3173095 (or 3173088 counting only the distinct ones).

The product of its (nonzero) digits is 4608, while the sum is 28.

Adding to 1431214443100 its reverse (13444121341), we get a palindrome (1444658564441).

The spelling of 1431214443100 in words is "one trillion, four hundred thirty-one billion, two hundred fourteen million, four hundred forty-three thousand, one hundred".