Base | Representation |
---|---|
bin | 1000110011110010010… |
… | …0110010011010110100 |
3 | 112110122011011021101211 |
4 | 2030330210302122310 |
5 | 4434421033211040 |
6 | 153305200131204 |
7 | 13635230616460 |
oct | 2147444623264 |
9 | 473564137354 |
10 | 151340132020 |
11 | 59201617180 |
12 | 253b7606b04 |
13 | 1136b0c909c |
14 | 747975b4a0 |
15 | 3e0b59a8ea |
hex | 233c9326b4 |
151340132020 has 96 divisors (see below), whose sum is σ = 413463730176. Its totient is φ = 45120028800.
The previous prime is 151340132011. The next prime is 151340132051. The reversal of 151340132020 is 20231043151.
It is a happy number.
It is a Harshad number since it is a multiple of its sum of digits (22).
It is a junction number, because it is equal to n+sod(n) for n = 151340131982 and 151340132000.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2100946 + ... + 2171785.
It is an arithmetic number, because the mean of its divisors is an integer number (4306913856).
Almost surely, 2151340132020 is an apocalyptic number.
151340132020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
151340132020 is an abundant number, since it is smaller than the sum of its proper divisors (262123598156).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
151340132020 is a wasteful number, since it uses less digits than its factorization.
151340132020 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4272781 (or 4272779 counting only the distinct ones).
The product of its (nonzero) digits is 720, while the sum is 22.
Adding to 151340132020 its reverse (20231043151), we get a palindrome (171571175171).
The spelling of 151340132020 in words is "one hundred fifty-one billion, three hundred forty million, one hundred thirty-two thousand, twenty".
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