Base | Representation |
---|---|
bin | 1000110011110111111… |
… | …0000000101101111000 |
3 | 112110200210011120121011 |
4 | 2030331332000231320 |
5 | 4434443030141100 |
6 | 153311353323304 |
7 | 13635633463210 |
oct | 2147576005570 |
9 | 473623146534 |
10 | 151363521400 |
11 | 59213841a43 |
12 | 25403406534 |
13 | 11372bc8160 |
14 | 747c8c9240 |
15 | 3e0d66abba |
hex | 233df80b78 |
151363521400 has 96 divisors (see below), whose sum is σ = 433132590240. Its totient is φ = 47904053760.
The previous prime is 151363521391. The next prime is 151363521403. The reversal of 151363521400 is 4125363151.
It is a super-2 number, since 2×1513635214002 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (151363521403) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 4140139 + ... + 4176538.
It is an arithmetic number, because the mean of its divisors is an integer number (4511797815).
Almost surely, 2151363521400 is an apocalyptic number.
151363521400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
151363521400 is an abundant number, since it is smaller than the sum of its proper divisors (281769068840).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
151363521400 is a wasteful number, since it uses less digits than its factorization.
151363521400 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8316713 (or 8316704 counting only the distinct ones).
The product of its (nonzero) digits is 10800, while the sum is 31.
Adding to 151363521400 its reverse (4125363151), we get a palindrome (155488884551).
The spelling of 151363521400 in words is "one hundred fifty-one billion, three hundred sixty-three million, five hundred twenty-one thousand, four hundred".
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