Base | Representation |
---|---|
bin | 1000110111011001110… |
… | …0110110110010100100 |
3 | 112120010211021011000010 |
4 | 2031312130312302210 |
5 | 4443413122200200 |
6 | 153545404050220 |
7 | 14001261153246 |
oct | 2156634666244 |
9 | 476124234003 |
10 | 152311131300 |
11 | 5965a732319 |
12 | 25628833970 |
13 | 11494321083 |
14 | 752c6ba096 |
15 | 3e6694e150 |
hex | 2376736ca4 |
152311131300 has 144 divisors (see below), whose sum is σ = 474681618432. Its totient is φ = 37597084800.
The previous prime is 152311131299. The next prime is 152311131311. The reversal of 152311131300 is 3131113251.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 142134 + ... + 569933.
It is an arithmetic number, because the mean of its divisors is an integer number (3296400128).
Almost surely, 2152311131300 is an apocalyptic number.
152311131300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
152311131300 is an abundant number, since it is smaller than the sum of its proper divisors (322370487132).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
152311131300 is a wasteful number, since it uses less digits than its factorization.
152311131300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 712138 (or 712131 counting only the distinct ones).
The product of its (nonzero) digits is 270, while the sum is 21.
Adding to 152311131300 its reverse (3131113251), we get a palindrome (155442244551).
The spelling of 152311131300 in words is "one hundred fifty-two billion, three hundred eleven million, one hundred thirty-one thousand, three hundred".
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