Base | Representation |
---|---|
bin | 101101110001100101110111… |
… | …110100100011110001011000 |
3 | 222101211000010210201022112111 |
4 | 231301211313310203301120 |
5 | 202341411341124111440 |
6 | 1552101045322522104 |
7 | 60255614403104623 |
oct | 5561456764436130 |
9 | 871730123638474 |
10 | 201320012332120 |
11 | 591683796178a0 |
12 | 1a6b5200966334 |
13 | 884451b48b156 |
14 | 379dd24d84dba |
15 | 1841bded694ea |
hex | b71977d23c58 |
201320012332120 has 128 divisors (see below), whose sum is σ = 515714636989440. Its totient is φ = 70013383165440.
The previous prime is 201320012332099. The next prime is 201320012332123. The reversal of 201320012332120 is 21233210023102.
It is a Harshad number since it is a multiple of its sum of digits (22).
It is a junction number, because it is equal to n+sod(n) for n = 201320012332091 and 201320012332100.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (201320012332123) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 63182749 + ... + 66292531.
It is an arithmetic number, because the mean of its divisors is an integer number (4029020601480).
Almost surely, 2201320012332120 is an apocalyptic number.
201320012332120 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 201320012332120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (257857318494720).
201320012332120 is an abundant number, since it is smaller than the sum of its proper divisors (314394624657320).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
201320012332120 is a wasteful number, since it uses less digits than its factorization.
201320012332120 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3116225 (or 3116221 counting only the distinct ones).
The product of its (nonzero) digits is 864, while the sum is 22.
Adding to 201320012332120 its reverse (21233210023102), we get a palindrome (222553222355222).
The spelling of 201320012332120 in words is "two hundred one trillion, three hundred twenty billion, twelve million, three hundred thirty-two thousand, one hundred twenty".
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