| Base | Representation |
|---|---|
| bin | 1100011010101110100… |
| … | …1010001010000000000 |
| 3 | 202101122112220100200200 |
| 4 | 3012223221101100000 |
| 5 | 11443401234320000 |
| 6 | 242000501045200 |
| 7 | 21261410412660 |
| oct | 3065351212000 |
| 9 | 671575810620 |
| 10 | 213333120000 |
| 11 | 82523a91640 |
| 12 | 354189b6800 |
| 13 | 1716a716ab0 |
| 14 | a47aba21a0 |
| 15 | 5838c78500 |
| hex | 31aba51400 |
213333120000 has 2640 divisors, whose sum is σ = 1061439130752. Its totient is φ = 39813120000.
The previous prime is 213333119981. The next prime is 213333120023. The reversal of 213333120000 is 21333312.
213333120000 is a `hidden beast` number, since 2 + 133 + 331 + 200 + 0 + 0 = 666.
It is a tau number, because it is divible by the number of its divisors (2640).
It is a super-2 number, since 2×2133331200002 (a number of 23 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 239 ways as a sum of consecutive naturals, for example, 5765759982 + ... + 5765760018.
Almost surely, 2213333120000 is an apocalyptic number.
213333120000 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 213333120000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (530719565376).
213333120000 is an abundant number, since it is smaller than the sum of its proper divisors (848106010752).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
213333120000 is a wasteful number, since it uses less digits than its factorization.
213333120000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 114 (or 78 counting only the distinct ones).
The product of its (nonzero) digits is 324, while the sum is 18.
Adding to 213333120000 its reverse (21333312), we get a palindrome (213354453312).
213333120000 divided by its reverse (21333312) gives a 4-th power (10000 = 104).
It can be divided in two parts, 213333 and 120000, that added together give a palindrome (333333).
The spelling of 213333120000 in words is "two hundred thirteen billion, three hundred thirty-three million, one hundred twenty thousand".
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