Base | Representation |
---|---|
bin | 11111010000100110101… |
… | …110011000100011011000 |
3 | 21121100201002212021121221 |
4 | 133100212232120203120 |
5 | 240143334113411100 |
6 | 4322501104341424 |
7 | 311124514062664 |
oct | 37204656304330 |
9 | 7540632767557 |
10 | 2148133341400 |
11 | 7590222a6782 |
12 | 2a83a5614874 |
13 | 127750184ac7 |
14 | 75d823758a4 |
15 | 3ad27c8801a |
hex | 1f426b988d8 |
2148133341400 has 48 divisors (see below), whose sum is σ = 5211558291600. Its totient is φ = 821894494080.
The previous prime is 2148133341337. The next prime is 2148133341443. The reversal of 2148133341400 is 41433318412.
It is a super-2 number, since 2×21481333414002 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 233488155 + ... + 233497354.
It is an arithmetic number, because the mean of its divisors is an integer number (108574131075).
Almost surely, 22148133341400 is an apocalyptic number.
2148133341400 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
2148133341400 is an abundant number, since it is smaller than the sum of its proper divisors (3063424950200).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
2148133341400 is a wasteful number, since it uses less digits than its factorization.
2148133341400 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 466985548 (or 466985539 counting only the distinct ones).
The product of its (nonzero) digits is 27648, while the sum is 34.
Adding to 2148133341400 its reverse (41433318412), we get a palindrome (2189566659812).
The spelling of 2148133341400 in words is "two trillion, one hundred forty-eight billion, one hundred thirty-three million, three hundred forty-one thousand, four hundred".
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