311414112 has 96 divisors (see below), whose sum is σ = 947842560. Its totient is φ = 99285120.

The previous prime is 311414107. The next prime is 311414113. The reversal of 311414112 is 211414113.

It is a tau number, because it is divible by the number of its divisors (96).

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a nude number because it is divisible by every one of its digits and also a Zuckerman number because it is divisible by the product of its digits.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (311414113) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 12037 + ... + 27707.

It is an arithmetic number, because the mean of its divisors is an integer number (9873360).

Almost surely, 2^311414112 is an apocalyptic number.

311414112 is a gapful number since it is divisible by the number (32) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 311414112, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (473921280).

311414112 is an abundant number, since it is smaller than the sum of its proper divisors (636428448).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

311414112 is a wasteful number, since it uses less digits than its factorization.

311414112 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 15713 (or 15699 counting only the distinct ones).

The product of its digits is 96, while the sum is 18.

The square root of 311414112 is about 17646.9292512890. The cubic root of 311414112 is about 677.8174776909.

Adding to 311414112 its reverse (211414113), we get a palindrome (522828225).

Subtracting from 311414112 its reverse (211414113), we obtain a palindrome (99999999).

It can be divided in two parts, 31141 and 4112, that added together give a palindrome (35253).

The spelling of 311414112 in words is "three hundred eleven million, four hundred fourteen thousand, one hundred twelve".