Base | Representation |
---|---|
bin | 101101011011100110011… |
… | …110111000001101010000 |
3 | 102001110110110110112020200 |
4 | 231123212132320031100 |
5 | 402122340324023440 |
6 | 10350122155535200 |
7 | 441362252406111 |
oct | 55334636701520 |
9 | 12043413415220 |
10 | 3122013111120 |
11 | aa4047012aa2 |
12 | 425097a5a500 |
13 | 198534b02287 |
14 | ab16b74c208 |
15 | 563262ebc30 |
hex | 2d6e67b8350 |
3122013111120 has 60 divisors (see below), whose sum is σ = 10484760700596. Its totient is φ = 832536829440.
The previous prime is 3122013111103. The next prime is 3122013111163. The reversal of 3122013111120 is 211113102213.
3122013111120 is a `hidden beast` number, since 31 + 2 + 201 + 311 + 1 + 120 = 666.
It can be written as a sum of positive squares in 2 ways, for example, as 1184248885824 + 1937764225296 = 1088232^2 + 1392036^2 .
It is a tau number, because it is divible by the number of its divisors (60).
It is a Harshad number since it is a multiple of its sum of digits (18).
It is a junction number, because it is equal to n+sod(n) for n = 3122013111093 and 3122013111102.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 2168063941 + ... + 2168065380.
Almost surely, 23122013111120 is an apocalyptic number.
3122013111120 is a gapful number since it is divisible by the number (30) formed by its first and last digit.
It is an amenable number.
3122013111120 is an abundant number, since it is smaller than the sum of its proper divisors (7362747589476).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
3122013111120 is a wasteful number, since it uses less digits than its factorization.
3122013111120 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4336129340 (or 4336129331 counting only the distinct ones).
The product of its (nonzero) digits is 72, while the sum is 18.
Adding to 3122013111120 its reverse (211113102213), we get a palindrome (3333126213333).
The spelling of 3122013111120 in words is "three trillion, one hundred twenty-two billion, thirteen million, one hundred eleven thousand, one hundred twenty".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.068 sec. • engine limits •