Base | Representation |
---|---|
bin | 1110010101001010010010… |
… | …10101000001110100100000 |
3 | 11010120122121101202200202021 |
4 | 13022211021111001310200 |
5 | 13112303423224100000 |
6 | 151005020351031224 |
7 | 6431524363240111 |
oct | 712451125016440 |
9 | 133518541680667 |
10 | 31513405300000 |
11 | a04a83a814778 |
12 | 364b61380b514 |
13 | 1477916ba3320 |
14 | 7ad385126208 |
15 | 399b08e8411a |
hex | 1ca949541d20 |
31513405300000 has 144 divisors (see below), whose sum is σ = 83512757669544. Its totient is φ = 11635718400000.
The previous prime is 31513405299991. The next prime is 31513405300019. The reversal of 31513405300000 is 350431513.
It can be written as a sum of positive squares in 12 ways, for example, as 17316817177104 + 14196588122896 = 4161348^2 + 3767836^2 .
It is a Harshad number since it is a multiple of its sum of digits (25).
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 10820541 + ... + 13420540.
Almost surely, 231513405300000 is an apocalyptic number.
It is an amenable number.
31513405300000 is an abundant number, since it is smaller than the sum of its proper divisors (51999352369544).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
31513405300000 is an equidigital number, since it uses as much as digits as its factorization.
31513405300000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 24241129 (or 24241101 counting only the distinct ones).
The product of its (nonzero) digits is 2700, while the sum is 25.
Adding to 31513405300000 its reverse (350431513), we get a palindrome (31513755731513).
The spelling of 31513405300000 in words is "thirty-one trillion, five hundred thirteen billion, four hundred five million, three hundred thousand".
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