Base | Representation |
---|---|
bin | 100000000010100010… |
… | …011001110010011100 |
3 | 10021210120000111012200 |
4 | 200002202121302130 |
5 | 1030423442430244 |
6 | 23445412531500 |
7 | 2325343551513 |
oct | 400242316234 |
9 | 107716014180 |
10 | 34402311324 |
11 | 13654231757 |
12 | 6801320b90 |
13 | 3323457144 |
14 | 1944da567a |
15 | d6536c669 |
hex | 802899c9c |
34402311324 has 72 divisors (see below), whose sum is σ = 94322618208. Its totient is φ = 10529633280.
The previous prime is 34402311323. The next prime is 34402311353. The reversal of 34402311324 is 42311320443.
34402311324 is a `hidden beast` number, since 344 + 0 + 2 + 311 + 3 + 2 + 4 = 666.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (34402311323) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 660432 + ... + 710615.
It is an arithmetic number, because the mean of its divisors is an integer number (1310036364).
Almost surely, 234402311324 is an apocalyptic number.
34402311324 is a gapful number since it is divisible by the number (34) formed by its first and last digit.
It is an amenable number.
34402311324 is an abundant number, since it is smaller than the sum of its proper divisors (59920306884).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
34402311324 is a wasteful number, since it uses less digits than its factorization.
34402311324 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1371115 (or 1371110 counting only the distinct ones).
The product of its (nonzero) digits is 6912, while the sum is 27.
Adding to 34402311324 its reverse (42311320443), we get a palindrome (76713631767).
The spelling of 34402311324 in words is "thirty-four billion, four hundred two million, three hundred eleven thousand, three hundred twenty-four".
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