Base | Representation |
---|---|
bin | 10010101101011011000001… |
… | …01000101111011111011000 |
3 | 12101200020120021202012002121 |
4 | 21112231200220233133120 |
5 | 20343042043413141100 |
6 | 223300515111311024 |
7 | 11444330460312145 |
oct | 1126554050573730 |
9 | 171606507665077 |
10 | 41143113021400 |
11 | 1212277277a165 |
12 | 474598937b474 |
13 | 19c5a1835c190 |
14 | a234a17773cc |
15 | 4b536062151a |
hex | 256b60a2f7d8 |
41143113021400 has 96 divisors (see below), whose sum is σ = 103017758160240. Its totient is φ = 15191047733760.
The previous prime is 41143113021349. The next prime is 41143113021421. The reversal of 41143113021400 is 412031134114.
It is a Harshad number since it is a multiple of its sum of digits (25).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 232941922 + ... + 233118478.
Almost surely, 241143113021400 is an apocalyptic number.
41143113021400 is a gapful number since it is divisible by the number (40) formed by its first and last digit.
It is an amenable number.
41143113021400 is an abundant number, since it is smaller than the sum of its proper divisors (61874645138840).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
41143113021400 is a wasteful number, since it uses less digits than its factorization.
41143113021400 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 266213 (or 266204 counting only the distinct ones).
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 41143113021400 its reverse (412031134114), we get a palindrome (41555144155514).
The spelling of 41143113021400 in words is "forty-one trillion, one hundred forty-three billion, one hundred thirteen million, twenty-one thousand, four hundred".
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