Base | Representation |
---|---|
bin | 100101001100100010000… |
… | …0001000011111001100000 |
3 | 200002201100200021202022021 |
4 | 1022121010001003321200 |
5 | 1132224141431223130 |
6 | 14512253523351224 |
7 | 1035224616553300 |
oct | 112310401037140 |
9 | 20081320252267 |
10 | 5112152211040 |
11 | 16a1062716686 |
12 | 6a6929522514 |
13 | 2b10c642c914 |
14 | 139602727600 |
15 | 8cea374637a |
hex | 4a644043e60 |
5112152211040 has 144 divisors (see below), whose sum is σ = 14502493321344. Its totient is φ = 1696197888000.
The previous prime is 5112152210983. The next prime is 5112152211043. The reversal of 5112152211040 is 401122512115.
It is a super-2 number, since 2×51121522110402 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 5112152210996 and 5112152211014.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5112152211043) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 10274061 + ... + 10760140.
It is an arithmetic number, because the mean of its divisors is an integer number (100711759176).
Almost surely, 25112152211040 is an apocalyptic number.
It is an amenable number.
5112152211040 is an abundant number, since it is smaller than the sum of its proper divisors (9390341110304).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
5112152211040 is a wasteful number, since it uses less digits than its factorization.
5112152211040 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 21034261 (or 21034246 counting only the distinct ones).
The product of its (nonzero) digits is 800, while the sum is 25.
Adding to 5112152211040 its reverse (401122512115), we get a palindrome (5513274723155).
The spelling of 5112152211040 in words is "five trillion, one hundred twelve billion, one hundred fifty-two million, two hundred eleven thousand, forty".
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