Base | Representation |
---|---|
bin | 100110110100011101100… |
… | …0110110110101110100000 |
3 | 200220001110002102201100022 |
4 | 1031220323012312232200 |
5 | 1144403234301100100 |
6 | 15203004414413012 |
7 | 1060315503344306 |
oct | 115507306665640 |
9 | 20801402381308 |
10 | 5335341034400 |
11 | 1777783a16003 |
12 | 722036b01168 |
13 | 2c9174980c40 |
14 | 14633640a276 |
15 | 93bb7877e85 |
hex | 4da3b1b6ba0 |
5335341034400 has 72 divisors (see below), whose sum is σ = 14026816812204. Its totient is φ = 1969972070400.
The previous prime is 5335341034367. The next prime is 5335341034417. The reversal of 5335341034400 is 44301435335.
It can be written as a sum of positive squares in 6 ways, for example, as 1833846806416 + 3501494227984 = 1354196^2 + 1871228^2 .
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 256496381 + ... + 256517180.
Almost surely, 25335341034400 is an apocalyptic number.
5335341034400 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
It is an amenable number.
5335341034400 is an abundant number, since it is smaller than the sum of its proper divisors (8691475777804).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
5335341034400 is a wasteful number, since it uses less digits than its factorization.
5335341034400 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 513013594 (or 513013581 counting only the distinct ones).
The product of its (nonzero) digits is 129600, while the sum is 35.
Adding to 5335341034400 its reverse (44301435335), we get a palindrome (5379642469735).
The spelling of 5335341034400 in words is "five trillion, three hundred thirty-five billion, three hundred forty-one million, thirty-four thousand, four hundred".
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