Base | Representation |
---|---|
bin | 10010110100010111… |
… | …11011111111000000 |
3 | 222002002121020211020 |
4 | 21122023323333000 |
5 | 131142332411222 |
6 | 4350302345440 |
7 | 505235124210 |
oct | 113213737700 |
9 | 28062536736 |
10 | 10103013312 |
11 | 4314984487 |
12 | 1b5b58b280 |
13 | c501476b2 |
14 | 6bbada240 |
15 | 3e1e5a65c |
hex | 25a2fbfc0 |
10103013312 has 56 divisors (see below), whose sum is σ = 30549591936. Its totient is φ = 2886574848.
The previous prime is 10103013307. The next prime is 10103013313. The reversal of 10103013312 is 21331030101.
It is a tau number, because it is divible by the number of its divisors (56).
It is a junction number, because it is equal to n+sod(n) for n = 10103013291 and 10103013300.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (10103013313) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3757218 + ... + 3759905.
Almost surely, 210103013312 is an apocalyptic number.
10103013312 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
10103013312 is an abundant number, since it is smaller than the sum of its proper divisors (20446578624).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
10103013312 is an equidigital number, since it uses as much as digits as its factorization.
10103013312 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7517145 (or 7517135 counting only the distinct ones).
The product of its (nonzero) digits is 54, while the sum is 15.
Adding to 10103013312 its reverse (21331030101), we get a palindrome (31434043413).
The spelling of 10103013312 in words is "ten billion, one hundred three million, thirteen thousand, three hundred twelve".
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