| Base | Representation |
|---|---|
| bin | 10010110111100101… |
| … | …11011110010000000 |
| 3 | 222010222101222212020 |
| 4 | 21123302323302000 |
| 5 | 131221240411222 |
| 6 | 4353105201440 |
| 7 | 506013456336 |
| oct | 113362736200 |
| 9 | 28128358766 |
| 10 | 10130013312 |
| 11 | 4329145a31 |
| 12 | 1b68630280 |
| 13 | c5590c023 |
| 14 | 6c1527b56 |
| 15 | 3e44e065c |
| hex | 25bcbbc80 |
10130013312 has 128 divisors (see below), whose sum is σ = 28958860800. Its totient is φ = 3125821440.
The previous prime is 10130013281. The next prime is 10130013317. The reversal of 10130013312 is 21331003101.
10130013312 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a tau number, because it is divible by the number of its divisors (128).
It is a junction number, because it is equal to n+sod(n) for n = 10130013291 and 10130013300.
It is not an unprimeable number, because it can be changed into a prime (10130013317) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 385489 + ... + 410927.
It is an arithmetic number, because the mean of its divisors is an integer number (226241100).
Almost surely, 210130013312 is an apocalyptic number.
10130013312 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 10130013312, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (14479430400).
10130013312 is an abundant number, since it is smaller than the sum of its proper divisors (18828847488).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
10130013312 is a wasteful number, since it uses less digits than its factorization.
10130013312 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 25534 (or 25522 counting only the distinct ones).
The product of its (nonzero) digits is 54, while the sum is 15.
Adding to 10130013312 its reverse (21331003101), we get a palindrome (31461016413).
The spelling of 10130013312 in words is "ten billion, one hundred thirty million, thirteen thousand, three hundred twelve".
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