| Base | Representation |
|---|---|
| bin | 110011110000000001… |
| … | …1001011101100100000 |
| 3 | 101121212001120002100200 |
| 4 | 1213200003023230200 |
| 5 | 3310100034104440 |
| 6 | 123015344145200 |
| 7 | 11012660606151 |
| oct | 1474003135440 |
| 9 | 347761502320 |
| 10 | 111133113120 |
| 11 | 43149821837 |
| 12 | 19656308200 |
| 13 | a6311a2843 |
| 14 | 55438a1928 |
| 15 | 2d5681ec30 |
| hex | 19e00cbb20 |
111133113120 has 144 divisors (see below), whose sum is σ = 381569190912. Its totient is φ = 29453621760.
The previous prime is 111133113097. The next prime is 111133113137. The reversal of 111133113120 is 21311331111.
111133113120 is a `hidden beast` number, since 11 + 11 + 331 + 1 + 312 + 0 = 666.
It is a tau number, because it is divible by the number of its divisors (144).
It is a super-2 number, since 2×1111331131202 (a number of 23 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is a junction number, because it is equal to n+sod(n) for n = 111133113093 and 111133113102.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 2016 + ... + 471455.
It is an arithmetic number, because the mean of its divisors is an integer number (2649786048).
Almost surely, 2111133113120 is an apocalyptic number.
111133113120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 111133113120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (190784595456).
111133113120 is an abundant number, since it is smaller than the sum of its proper divisors (270436077792).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
111133113120 is a wasteful number, since it uses less digits than its factorization.
111133113120 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 473655 (or 473644 counting only the distinct ones).
The product of its (nonzero) digits is 54, while the sum is 18.
Adding to 111133113120 its reverse (21311331111), we get a palindrome (132444444231).
The spelling of 111133113120 in words is "one hundred eleven billion, one hundred thirty-three million, one hundred thirteen thousand, one hundred twenty".
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