Base | Representation |
---|---|
bin | 1010000111110110101011… |
… | …1011101101001101011110 |
3 | 1110102000121121202200020020 |
4 | 2201331222323231031132 |
5 | 2424323322400104020 |
6 | 35401024254333010 |
7 | 2226056056406235 |
oct | 241755273551536 |
9 | 43360547680206 |
10 | 11130054300510 |
11 | 36012585468a2 |
12 | 12b90b47ba166 |
13 | 62973762b562 |
14 | 2a69a9d37b1c |
15 | 1447b9196c40 |
hex | a1f6aeed35e |
11130054300510 has 96 divisors (see below), whose sum is σ = 28078306427808. Its totient is φ = 2823284724480.
The previous prime is 11130054300493. The next prime is 11130054300527. The reversal of 11130054300510 is 1500345003111.
It is an interprime number because it is at equal distance from previous prime (11130054300493) and next prime (11130054300527).
It is a super-2 number, since 2×111300543005102 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 935104 + ... + 4809836.
It is an arithmetic number, because the mean of its divisors is an integer number (292482358623).
Almost surely, 211130054300510 is an apocalyptic number.
11130054300510 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is a practical number, because each smaller number is the sum of distinct divisors of 11130054300510, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (14039153213904).
11130054300510 is an abundant number, since it is smaller than the sum of its proper divisors (16948252127298).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11130054300510 is a wasteful number, since it uses less digits than its factorization.
11130054300510 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3874970 (or 3874947 counting only the distinct ones).
The product of its (nonzero) digits is 900, while the sum is 24.
Adding to 11130054300510 its reverse (1500345003111), we get a palindrome (12630399303621).
The spelling of 11130054300510 in words is "eleven trillion, one hundred thirty billion, fifty-four million, three hundred thousand, five hundred ten".
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