111443330001300 has 72 divisors (see below), whose sum is σ = 351755674341792. Its totient is φ = 27016564848000.

The previous prime is 111443330001259. The next prime is 111443330001347. The reversal of 111443330001300 is 3100033344111.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 16885349731 + ... + 16885356330.

Almost surely, 2^{111443330001300} is an apocalyptic number.

111443330001300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

111443330001300 is an abundant number, since it is smaller than the sum of its proper divisors (240312344340492).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

111443330001300 is a wasteful number, since it uses less digits than its factorization.

111443330001300 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 33770706089 (or 33770706082 counting only the distinct ones).

The product of its (nonzero) digits is 1296, while the sum is 24.

Adding to 111443330001300 its reverse (3100033344111), we get a palindrome (114543363345411).

The spelling of 111443330001300 in words is "one hundred eleven trillion, four hundred forty-three billion, three hundred thirty million, one thousand, three hundred".