Search a number
-
+
1131213303120 = 243529373435739
BaseRepresentation
bin10000011101100001100…
…100010010110101010000
311000010212012101212002110
4100131201210102311100
5122013211101144440
62223401110545320
7144504343266165
oct20354144226520
94003765355073
101131213303120
113a682146767a
121632a1068240
13828996419c4
143ca72b0606c
151e65ad92080
hex10761912d50

1131213303120 has 160 divisors (see below), whose sum is σ = 3637418083200. Its totient is φ = 290473408512.

The previous prime is 1131213303107. The next prime is 1131213303133. The reversal of 1131213303120 is 213033121311.

It is a happy number.

It is an interprime number because it is at equal distance from previous prime (1131213303107) and next prime (1131213303133).

It is a super-2 number, since 2×11312133031202 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2378211 + ... + 2813949.

It is an arithmetic number, because the mean of its divisors is an integer number (22733863020).

Almost surely, 21131213303120 is an apocalyptic number.

1131213303120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1131213303120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1818709041600).

1131213303120 is an abundant number, since it is smaller than the sum of its proper divisors (2506204780080).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1131213303120 is a wasteful number, since it uses less digits than its factorization.

1131213303120 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 436157 (or 436151 counting only the distinct ones).

The product of its (nonzero) digits is 324, while the sum is 21.

Adding to 1131213303120 its reverse (213033121311), we get a palindrome (1344246424431).

The spelling of 1131213303120 in words is "one trillion, one hundred thirty-one billion, two hundred thirteen million, three hundred three thousand, one hundred twenty".

Divisors: 1 2 3 4 5 6 8 10 12 15 16 20 24 29 30 40 48 58 60 80 87 116 120 145 174 232 240 290 348 373 435 464 580 696 746 870 1119 1160 1392 1492 1740 1865 2238 2320 2984 3480 3730 4476 5595 5968 6960 7460 8952 10817 11190 14920 17904 21634 22380 29840 32451 43268 44760 54085 64902 86536 89520 108170 129804 162255 173072 216340 259608 324510 432680 435739 519216 649020 865360 871478 1298040 1307217 1742956 2178695 2596080 2614434 3485912 4357390 5228868 6536085 6971824 8714780 10457736 12636431 13072170 17429560 20915472 25272862 26144340 34859120 37909293 50545724 52288680 63182155 75818586 101091448 104577360 126364310 151637172 162530647 189546465 202182896 252728620 303274344 325061294 379092930 487591941 505457240 606548688 650122588 758185860 812653235 975183882 1010914480 1300245176 1516371720 1625306470 1950367764 2437959705 2600490352 3032743440 3250612940 3900735528 4713388763 4875919410 6501225880 7801471056 9426777526 9751838820 13002451760 14140166289 18853555052 19503677640 23566943815 28280332578 37707110104 39007355280 47133887630 56560665156 70700831445 75414220208 94267775260 113121330312 141401662890 188535550520 226242660624 282803325780 377071101040 565606651560 1131213303120